60^2=4w+w^2

Solution for 60^2=4w+w^2 equation:

60^2=4w+w^2

We move all terms to the left:

60^2-(4w+w^2)=0

We add all the numbers together, and all the variables

-(4w+w^2)+3600=0

We get rid of parentheses

-w^2-4w+3600=0

We add all the numbers together, and all the variables

-1w^2-4w+3600=0

a = -1; b = -4; c = +3600;
Δ = b2-4ac
Δ = -42-4·(-1)·3600
Δ = 14416
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{14416}=\sqrt{16*901}=\sqrt{16}*\sqrt{901}=4\sqrt{901}$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-4\sqrt{901}}{2*-1}=\frac{4-4\sqrt{901}}{-2}
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+4\sqrt{901}}{2*-1}=\frac{4+4\sqrt{901}}{-2}
$